(B)
CH4 demonstrates 109.5° between the C-H bonds, while XeF4 demonstrates 90° angles between its Xe-F bonds. Even though the formulas are similar, the different geometry is a result of the larger size of the Xe atom and the highly electronegative F atoms creating an "expanded octet." Two other pairs of unbonded electron pairs around Xenon also take up space, forcing the bonds to fluorine to be closer together than the C-H bonds in methane.